3x^2+12x=2x+83x2+12x=2x+8

Solution for 3x^2+12x=2x+83x2+12x=2x+8 equation:

3x^2+12x=2x+83x^2+12x=2x+8

We move all terms to the left:

3x^2+12x-(2x+83x^2+12x)=0

We get rid of parentheses

3x^2-83x^2-2x-12x+12x=0

We add all the numbers together, and all the variables

-80x^2-2x=0

a = -80; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-80)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-80}=\frac{0}{-160}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-80}=\frac{4}{-160}
=-1/40
$